RE: Query help !!!

From: Toepke, Kevin M <ktoepke_at_cms.cendant.com>
Date: Fri, 22 Jun 2001 10:18:51 -0700
Message-ID: <F001.00333FE3.20010622103428@fatcity.com>

SELECT *
FROM customer c1
WHERE status = 'F'
AND EXISTS (SELECT 1

       FROM customer c2
        WHERE c2.customer_id = c1.customer_id
        AND     c2.status != 'F');

-----Original Message-----
Sent: Friday, June 22, 2001 2:06 PM
To: Multiple recipients of list ORACLE-L

Just to clearfy my previous question (as follow):

if 1 has F and A and B, that what I want.

If 1 has F all the time, that's not what I want. If 1 has A, B, C, but never F, that's not what I want either.

• Leslie Lu <leslie_y_lu_at_yahoo.com> wrote:
  > Hi,
  >
  > If I have this:
  > Customer_id Status
  > ---------- -----------
  > 1 F
  > 1 A
  > 1 B
  > 2 F
  > 2 F
  > 3 A
  > 3 B
  >
  > How do I found out a customer who has both F and not
  > F
  > for them. (If he only gets F, or gets other than F,
  > that's fine). In this case, I should get 1. Thank
  > you! I need this badly!
  >
  > __________________________________________________
  > Do You Yahoo!?
  > Get personalized email addresses from Yahoo! Mail
  > http://personal.mail.yahoo.com/
  >
  

  ---

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-- 
Author: Leslie Lu
  INET: leslie_y_lu_at_yahoo.com

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-- 
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-- 
Author: Toepke, Kevin M
  INET: ktoepke_at_cms.cendant.com

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Received on Fri Jun 22 2001 - 12:18:51 CDT