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Home -> Community -> Mailing Lists -> Oracle-L -> Re: how to substr '%' from the data?
Helen,
try this instead,, It should help
select substr(mystring,1,(instr(mystring,'%') -1))
from mytable
eg below
DEV>create mytable (mystring varchar2(10));
Table created
DEV>insert into mytable values ('abcdefgh%jkl');
1 row created
DEV>insert into mytable values ('a%cdefghjkl');
1 row created
DEV>commit;
Commit complete
DEV>select substr(mystring,1,(instr(mystring,'%') -1))
2 from mytable
3 /
substr(mystring,1,(
2 rows selected
DEV> Brian.
Helen rwulfjeq <lannyue_at_yahoo.com>@fatcity.com on 06/11/2001 06:06:35 PM
Please respond to ORACLE-L_at_fatcity.com
Sent by: root_at_fatcity.com
To: Multiple recipients of list ORACLE-L <ORACLE-L_at_fatcity.com> cc:
Hello,
I have data like following, how do I substr the string (or use any other function) to get until "%" and return without "%":
RC-SF-DAL-nd-%
AD-LE-%-%-%
RC-DD-LKF-01-RENTAL% CS-%-%-%-%
CS-%-ABC-%-%
I did "select RTRIM('CS-%-%-%-%', '%-%') from DUAL", but it can not return correct for the last record
eg, "select RTRIM(CS-%-ABC-%-%', '%-%') from DUAL" -- will not work correctly
Thanks for help
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