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DONE script enclosed: shell script to compare nos.

From: Viraj Luthra <viraj999_at_lycos.com>
Date: Wed, 11 Apr 2001 18:09:34 -0700
Message-ID: <F001.002E7ACD.20010411175527@fatcity.com>

 Hello every one,

Thanks for the awk script sent before, I could not use ask as some sites dont have awk but have nawk, so my script will fail. So alternatively devised this shell script, which does the job:-

#!/bin/sh                                         
                                                  
                                    
olddir="7.04.03"                                  
olddir1="`echo $olddir| cut -c1 `"                
olddir2="`echo $olddir| cut -f2 -d"." `"          
olddir3="`echo $olddir| cut -f3 -d"." `"          
if [ "$olddir3" = "" ]; then                      
  olddir3=00                                      
fi
fullversion="$olddir1""$olddir2""$olddir3"
VER="7.05"                                 
ver1="`echo $VER| cut -c1 `"               
ver2="`echo $VER| cut -f2 -d"." `"         
ver3="`echo $VER| cut -f3 -d"." `"         
if [ "$ver3" = "" ]; then                      
  ver3="00"                                    
#  echo "The third version value  is $ver3"    
fi                                             
fullver="$ver1""$ver2""$ver3"      
if [ "$fullversion" -gt  "$fullver" ];then                           
   echo "The $olddir version  is greater than $VER version"      
elif [ "$fullversion" -lt "$fullver" ];then                          
   echo "The $olddir  version is less than $VER version"         
else                                                                 
   echo "Both versions are equal"                                    
fi                                                                   

==============================================

Basically I strip away the release nos. like instead of accepting 7.04.03, I accept it as 70403 and then compare and output.

Thanks for help.

Regrads,

Raja

On Wed, 11 Apr 2001 02:30:36
 lerobe - Lee Robertson wrote:
>Why not simply do the following passing two parameters to the script eg.
>call the script test.sh and call it so
>
>test.sh 2 1
>
>This results in output "VAR1 is greater than VAR2"
>
>then
>
>test.sh 1 2
>
>this results in output "VAR2 is greater than VAR1"
>
>Cheers.
>
>#!/bin/ksh
>VAR1=$1
>VAR2=$2
>if [ "$VAR1" -gt "$VAR2" ]
>then
>echo "VAR1 is greater than VAR2"
>else
>echo "VAR2 is greater than VAR1"
>fi
>
>
>
>-----Original Message-----
>Sent: 11 April 2001 10:01
>To: Multiple recipients of list ORACLE-L
>
>
>Hi
>I'm sure there are better ways but awk does the trick
>
>echo $var1 $var2 | awk '{ if ( $1 > $2 ) { print "1"} else { print"0" } }'
>
>cheers alex
>
>> Hello,
>>
>> I need some help in comparing 2 nos. in a unix shell.
>>
>> 1) e.g var1="7.04.03"
>> and var2="7.05"
>>
>> I want to test:-
>>
>> if [ "$var2" > "$var1" ];then
>> then $var2 version is greater than $var1"
>> fi
>>
>> 2) 2nd condition is :-
>>
>> var1="7.04.03"
>> var2="7.04.02"
>>
>> I want to test:-
>> if [ "$var1" > "$var2" ];then
>> then $var1 version is greater than $var2"
>> fi
>>
>> Can some one send me a code?
>>
>> How can I do the above in shell? Can you please help me, a seemingly
>simple
>> one!
>>
>>
>> Raja
>>
>>
>>
>> Get 250 color business cards for FREE! at Lycos Mail
>> http://mail.lycos.com/freemail/vistaprint_index.html
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>Author: lerobe - Lee Robertson
> INET: LEROBE_at_acxiom.co.uk
>
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Get 250 color business cards for FREE! at Lycos Mail http://mail.lycos.com/freemail/vistaprint_index.html

-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Viraj Luthra
  INET: viraj999_at_lycos.com

Fat City Network Services    -- (858) 538-5051  FAX: (858) 538-5051
San Diego, California        -- Public Internet access / Mailing Lists
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To REMOVE yourself from this mailing list, send an E-Mail message
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also send the HELP command for other information (like subscribing).
Received on Wed Apr 11 2001 - 20:09:34 CDT

Original text of this message

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