select a.sequence_nmbr, count(sequence_nmbr)
from TABLE_A a
group by a.sequence_nmbr
having count (sequence_nmbr) = (select count(temp_sequence_nmbr)) from TABLE_B b
where a.sequence_nmbr = b.temp_sequence_nmbr
)
order by a.sequence_nmbr;

select a.sequence_nmbr
  from a
 group by a.sequence_nmbr
 having count(*) <> (select count(*)
                       from b 
                      where a.sequence_nmbr = b.temp_sequence_nmbr);