OraFAQ Forum: SQL & PL/SQL » regular expression problem

Home » SQL & PL/SQL » SQL & PL/SQL » regular expression problem

Show: Today's Messages :: Polls :: Message Navigator
E-mail to friend

regular expression problem [message #190152]

Tue, 29 August 2006 07:42

sabrieker
Messages: 8
Registered: August 2006
Location: turket

Junior Member

hello i need your help
here my code
select adres,adres_koy,regexp_substr
(adres,'(( MAH\.?)|(M\.)|(MH)|(CAD)|(CD)|(CAD\.)|(CDS)|(C\.))?(^[YENIMAHALLE]|^[USK]|^[SASK]|^[KAZASK])?([[:print:]]*)((SOK)|(SK\.)|( SK)|(SOKAK)|(SOKAK\.)|(SOK\.))',
regexp_instr(adres,'(( MAH\.?)|(M\.)|(MH)|(CAD)|(CD)|(CAD\.)|(CDS)|(C\.))')+1)
from migros_source2

here i want to get substring from adres coloumn that is like this:
MERKEZ FEYZULLAH MH. TEMIZ SK.
here i want to get TEMIZ SK. part but my code takes H. TEMIZ SK.
but i dont want to get H. part also i dont want to use replace method because i have half million document
can u help me

or i explain this i want part of adres coloumn which is between MH. and SK. part but my code gives me MH. TEMIZ SK.
i am looking for TEMIZ SK. it isnot important for me MH. part

and why doesnt this one work

update migros_source set adres_belde=regexp_substr(adres_koy,'([[:print:]]*) CAD')
where regexp_like(adres_koy,'CAD')

Report message to a moderator

Re: regular expression problem [message #190161 is a reply to message #190152]

Tue, 29 August 2006 08:44

ebrian
Messages: 2794
Registered: April 2006

Senior Member

SQL> select regexp_substr('MERKEZ FEYZULLAH MH. TEMIZ SK.','\w+\s\w+\.$') "Name" from dual;

Name
--------
TEMIZ SK.

Report message to a moderator

Previous Topic:	OUTPUT OF QUERY
Next Topic:	How do I find special characters using a regular expresion?

Goto Forum:

-=] Back to Top [=-

[ Syndicate this forum (XML) ] [

]

Current Time: Thu Jul 10 07:25:28 CDT 2025