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extract portion of strings [message #664810] Sat, 05 August 2017 07:54 Go to next message
m.abdulhaq
Messages: 225
Registered: April 2013
Location: Ajman
Senior Member
Hello experts,

I want to remove the portion of strings from the string having values like below.

COMPANY_ID=C02^PAYROLL_LIST_ID=2017081^
COMPANY_ID=C02^PAYROLL_LIST_ID=201709^
COMPANY_ID=C02^PAYROLL_LIST_ID=2017^
COMPANY_ID=C02^PAYROLL_LIST_ID=2017A^

the desired output i want is
 
C02 AND 2017081
C02 AND 201709
C02 AND 2017
C02 AND 2017A


[Updated on: Sat, 05 August 2017 07:54]

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Re: extract portion of strings [message #664811 is a reply to message #664810] Sat, 05 August 2017 07:59 Go to previous messageGo to next message
BlackSwan
Messages: 25639
Registered: January 2009
Location: SoCal
Senior Member
NOTHING is post above shows any relationship to Oracle DB

Explain in words how to decide what characters to keep & which characters are discarded.
from where does "AND" originate?
When can desired out only contain single string like "C01"?

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Re: extract portion of strings [message #664812 is a reply to message #664811] Sat, 05 August 2017 10:47 Go to previous messageGo to next message
m.abdulhaq
Messages: 225
Registered: April 2013
Location: Ajman
Senior Member
Sorry ! its my mistake , i need to extract first portion and second portion of the string starting after '=' and ending before '^' .


select substr(key_ref,instr(key_ref,'=',1,1)+1, ( instr(key_ref,'^',1,1) - instr(key_ref,'=',1,1))-1 ),
key_ref from    APPROVAL_ROUTING where  key_ref = 'COMPANY_ID=C02^PAYROLL_LIST_ID=2017081^'


Re: extract portion of strings [message #664814 is a reply to message #664812] Sat, 05 August 2017 13:14 Go to previous messageGo to next message
Solomon Yakobson
Messages: 2657
Registered: January 2010
Location: Connecticut, USA
Senior Member
SQL> WITH T AS (
  2             SELECT 'C02^PAYROLL_LIST_ID=2017081^' COMPANY_ID FROM DUAL
  3            )
  4  SELECT  REGEXP_SUBSTR(COMPANY_ID,'^[^^]+') C1,
  5          REGEXP_SUBSTR(COMPANY_ID,'=([^^]+)',1,1,NULL,1) C2
  6    FROM  T
  7  /

C1  C2
--- -------
C02 2017081

SQL>

SY.
Re: extract portion of strings [message #664822 is a reply to message #664814] Sat, 05 August 2017 22:23 Go to previous messageGo to next message
m.abdulhaq
Messages: 225
Registered: April 2013
Location: Ajman
Senior Member
thanks Solomon,but actually my string is starting from 'COMPANY_ID=' as given below.


WITH T AS (
               SELECT 'COMPANY_ID=C02^PAYROLL_LIST_ID=2017081^' COMPANY_ID FROM DUAL
              )
    SELECT  REGEXP_SUBSTR(COMPANY_ID,'^[^^]+') C1,
            REGEXP_SUBSTR(COMPANY_ID,'=([^^]+)',1,1,NULL,1) C2
      FROM  T

C1               C2
---              -------
COMPANY_ID=C02    C02



[Updated on: Sat, 05 August 2017 22:32]

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Re: extract portion of strings [message #664823 is a reply to message #664822] Sun, 06 August 2017 07:14 Go to previous messageGo to next message
Solomon Yakobson
Messages: 2657
Registered: January 2010
Location: Connecticut, USA
Senior Member
WITH T AS (
               SELECT 'COMPANY_ID=C02^PAYROLL_LIST_ID=2017081^' COMPANY_ID FROM DUAL
              )
    SELECT  REGEXP_SUBSTR(COMPANY_ID,'=([^^]+)',1,1,NULL,1) C1,
            REGEXP_SUBSTR(COMPANY_ID,'=([^^]+)',1,2,NULL,1) C2
      FROM  T
/

C1  C2
--- -------
C02 2017081

SQL>

SY.
Re: extract portion of strings [message #664861 is a reply to message #664823] Tue, 08 August 2017 23:09 Go to previous message
m.abdulhaq
Messages: 225
Registered: April 2013
Location: Ajman
Senior Member
thanks Solomon.
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