Home » SQL & PL/SQL » SQL & PL/SQL » Syntax for creating oracle type (Oracle 11g )
Syntax for creating oracle type [message #630524] Mon, 29 December 2014 16:14 Go to next message
Oracle_Walker
Messages: 71
Registered: January 2012
Location: United States
Member

Hi,

I need to create a new type in my database. I am using the below command to create the same,

create or replace type tabtype as table of number;


But I would like to know the exact syntax for the same. Please help.
Re: Syntax for creating oracle type [message #630527 is a reply to message #630524] Mon, 29 December 2014 17:03 Go to previous message
BlackSwan
Messages: 26766
Registered: January 2009
Location: SoCal
Senior Member
when all else fails, Read The Fine Manual yourself

https://docs.oracle.com/database/121/SQLRF/toc.htm
Previous Topic: Problem with nested FOR Loop
Next Topic: How to select distinct sql_id together with clob column
Goto Forum:
  


Current Time: Fri Apr 26 04:18:52 CDT 2024