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How to validate the alphanumeric and symbol in textbox [message #570549] Mon, 12 November 2012 01:43 Go to next message
pakrul.interxs
Messages: 5
Registered: November 2012
Location: Kuala Lumpur, Malaysia
Junior Member

I have created a form that have a button to check the character in the textbox is alphanumeric and symbol.
Here attached the code, that i tried from other post.
Can somebody fix this.
I tried a couple a week ..but cannot be resolved.
Thanks a lot.

Regards,
pakrul
Re: How to validate the alphanumeric and symbol in textbox [message #570570 is a reply to message #570549] Mon, 12 November 2012 06:35 Go to previous messageGo to next message
cookiemonster
Messages: 11287
Registered: September 2008
Location: Rainy Manchester
Senior Member
Next time post you code directly in the thread using code tags as described here: How to use [code] tags and make your code easier to read?
A lot people can't/won't download attachments.
It would also help if explained exactly how the code is not working - are you getting error? Does it do something you don't expect?

What you want can be done simply with the translate function:
SQL> SELECT trim(TRANSLATE('BASD$%',
                      'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&()''*+,-/:;<=>?_',
  2    3                        '                                                                          ')
  4             )
  5  FROM dual;

T
-


SQL> SELECT trim(TRANSLATE('BA12 %^%',
                      'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&()''*+,-/:;<=>?_',
  2    3                        '                                                                          ')
  4             )
FROM dual;  5

TRIM(TRANSLATE(
---------------
12  ^


If the string returned by the above is anything other than null then you have disallowed characters

[Updated on: Mon, 12 November 2012 06:35]

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Re: How to validate the alphanumeric and symbol in textbox [message #570618 is a reply to message #570570] Mon, 12 November 2012 23:07 Go to previous messageGo to next message
pakrul.interxs
Messages: 5
Registered: November 2012
Location: Kuala Lumpur, Malaysia
Junior Member

Based on code below.
First..if i put all alphaphet. it shows number(digit) error not the alphabet.
Second ..If i put the digit. It shows alphabet error..
Third...If I put alphabet and digit..it shows no symbol input..
forth... If I put alphabet, digit and symbol...stil it say.."No symbol input" and cannot be saved..
Is it my code wrong or I missed some thing.

If i put that code as a function and return the boolean...How to call it use "when the button pressed" in PL/SQL.
Thanks. Smile

DECLARE
 	
 	alert_button number;
 
chararray     VARCHAR2(52);
digitarray     VARCHAR2(20);
ischar          BOOLEAN;
isdigit          BOOLEAN;
ispunct          BOOLEAN;
m          INTEGER;
n          BOOLEAN;

i integer;
j integer;
punctarray     VARCHAR2(25);
 
BEGIN
   digitarray := '0123456789';
   chararray := 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
   punctarray := '!"#$%&()''*+,-/:;<=>?_';
 

 
   
   if :block1.BARU is null then
		alert_button := Show_Alert('password');
		go_item('block1.BARU');
		raise form_trigger_failure;
		-- check for minimum password length
	
		elsif length(:block1.BARU)< 8 then
	   alert_button := Show_Alert('panjang');
	   go_item('block1.BARU');
	   raise form_trigger_failure;
 
   -- check for common words
ELSIF :block1.baru IN ('welcome', 'password', 'oracle', 'computer', 'abcdef') THEN
    alert_button := Show_Alert('biasa');
	   go_item('block1.BARU');
	   raise form_trigger_failure;
	   
 end if;

go_block('block1');
   isdigit := FALSE;
   m := LENGTH(:block1.baru);
 
   FOR i IN 1..25 LOOP
      FOR j IN 1..m LOOP
         IF SUBSTR(:block1.baru,j,1) = SUBSTR(digitarray,i,1) THEN
            isdigit := TRUE;
            GOTO findchar;
         END IF;
      END LOOP;
   END LOOP;
 
   IF isdigit = FALSE THEN
      		alert_button := Show_Alert('digit');
		go_item('block1.BARU');
		raise form_trigger_failure;
   END IF;
 
   <<findchar>>
   ischar := FALSE;
   FOR i IN 1..LENGTH(chararray) LOOP
      FOR j IN 1..m LOOP
         IF SUBSTR(:block1.baru,j,1) = SUBSTR(chararray,i,1) THEN
            ischar := TRUE;
            GOTO findpunct;
         END IF;
      END LOOP;
   END LOOP;
 
   IF ischar = FALSE THEN
     		alert_button := Show_Alert('char');
		go_item('block1.BARU');
		raise form_trigger_failure;
   END IF;
 
   <<findpunct>>
   ispunct := FALSE;
   FOR i IN 1..LENGTH(punctarray) LOOP
      FOR k IN 1..m LOOP
         IF SUBSTR(:block1.baru,j,1) = SUBSTR(punctarray,i,1) THEN
            ispunct := TRUE;
           GOTO endsearch;
         END IF;
      END LOOP;
   END LOOP;
 
   IF ispunct = FALSE THEN
      		alert_button := Show_Alert('symbol');
		go_item('block1.BARU');
		raise form_trigger_failure;
     	
  end if;
         
 
  
<<endsearch>>
 
   	  FORMS_DDL('ALTER USER '||:block1.login||' IDENTIFIED BY '||:block1.BARU);
  
			commit;
			alert_button := Show_Alert('SUCCESS'); 
			exit_form;

  

END;

Re: How to validate the alphanumeric and symbol in textbox [message #570620 is a reply to message #570618] Tue, 13 November 2012 00:09 Go to previous messageGo to next message
Littlefoot
Messages: 19894
Registered: June 2005
Location: Croatia, Europe
Senior Member
Account Moderator
It is awfully formatted. Read link Cookiemonster provided once again, please.

As of your code: work on it some more! Show your debugging skills! If it is too complex now, start from scratch, solving ONE problem at a time (the first one you mentioned; when you are satisfied with it, move on to the second one, and so forth).

As of a function returning Boolean: depending on what it returns (TRUE because input string is OK, or FALSE because it is not; or, you might even turn the logic upside down and return FALSE if the string is OK, but that's rather confusing). Suppose that it returns TRUE for a valid input. Then you'd do something like this:
if f_input_ok then
   message('Congratulations, you did it right!');
else
   message('Nope, something went wrong');
end if;
Re: How to validate the alphanumeric and symbol in textbox [message #570621 is a reply to message #570620] Tue, 13 November 2012 00:19 Go to previous messageGo to next message
pakrul.interxs
Messages: 5
Registered: November 2012
Location: Kuala Lumpur, Malaysia
Junior Member

Ok. Thanks. I'll try to debug again..Smile
Re: How to validate the alphanumeric and symbol in textbox [message #570665 is a reply to message #570621] Tue, 13 November 2012 22:59 Go to previous message
pakrul.interxs
Messages: 5
Registered: November 2012
Location: Kuala Lumpur, Malaysia
Junior Member

Thanks to all i Just put like Cookiemonster say....
Then I got message success...................and everything is fine..
Thanks again..
 DECLARE
 	
alert_button number;
 
 
BEGIN
   
   if :block1.BARU is null then
		alert_button := Show_Alert('password');
		go_item('block1.BARU');
		raise form_trigger_failure;
		-- check for minimum password length
	
		elsif length(:block1.BARU)< 8 then
	   alert_button := Show_Alert('panjang');
	   go_item('block1.BARU');
	   raise form_trigger_failure;
 
   -- check for common words
ELSIF :block1.baru IN ('welcome', 'password', 'oracle', 'computer', 'abcdef') THEN
    alert_button := Show_Alert('biasa');
	   go_item('block1.BARU');
	   raise form_trigger_failure;
	   
elsif length(TRIM(TRANSLATE(:BLOCK1.BARU,'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ',' ') )) is null then
	 alert_button := Show_Alert('char');
	   go_item('block1.BARU');
	   raise form_trigger_failure;

elsif length(TRIM(TRANSLATE(:BLOCK1.BARU,'0123456789',' '))) is null then
	 alert_button := Show_Alert('digit');
	   go_item('block1.BARU');
	   raise form_trigger_failure;
	   

elsif length(TRIM(TRANSLATE(:BLOCK1.BARU,'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&()''*+,-/:;<=>?_',' ' ))) is null then
	 
 
   	  FORMS_DDL('ALTER USER '||:block1.login||' IDENTIFIED BY '||:block1.BARU);
  
			commit;
			alert_button := Show_Alert('SUCCESS'); 
			exit_form;

  end if;

END;
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